Mark Dominus wrote an article asking how to take advantage of Haskell’s type safety in a simple dicerolling simulation function for the game Yahtzee. He added wrapper types so that one cannot mistakenly apply the function to values that merely have the correct type “by accident”. He says the result is “unreadable” and “unmaintainable”. It certainly doesn’t look nice! I’d claim it’s not even of much practical safety benefit (although I suppose that depends on what the rest of the program looks like).
Mark says
I don’t claim this code is any good; I was just hacking around exploring the problem space. But it does do what I wanted.
But we can’t just expect to sprinkle type safety on a bad design and get something good. Type safety and good design are qualities that evolve symbiotically. By using type safety merely to make things safer for our callers we miss out on a host of benefits. Type safety should be used to guide us in the design of our implementations, which our callers never see. In fact I would argue that Mark is trying to add type safety in exactly the wrong way.
If there is an interface whose implementation we don’t control then all we can do is to slap a type safe wrapper on it and be done with it. That is of some benefit. On the other hand, if we do control the implementation then the type safe wrapper specifies invariants that we can take advantage of inside the implementation. They can help us write the implementation.
We should build type safe structures and combinators relevant to our domain and implement our solution in terms of those. Likewise we should look at our solution and factor out repeated patterns into type safe structures and combinators relevant to our domain. This is symbiotic evolution!
Type safety and good design proceed handinhand along the road of implementation evolution. Type safety nudges us in the direction of good design and good design nudges us in the direction of type safety. One of the reasons I prefer Haskell to other languages is that the compiler can enforce the type safety end of this bargain. On the other hand, there’s no reason a design in Python, say, can’t be guided by “type safety” in the same sense as a design in Haskell. It’s just that the “type safety” won’t be checked by any tooling and so there’s no evolutionary pressure in that direction (Python’s recent type annotations notwithstanding).
Let’s evolve Mark’s program in the direction of good design and see what arises. In this case, as we’ll see, I’m not sure there’s much to be gained by trying to “add type safety”. On the other hand, that there is much to be gained by improving the design guided by considerations of type safety. The design improvements would apply equally well to an implementation in Python.
I’ve shown the stages of program evolution as diffs. Sometimes they’re easy to read and sometimes they’re difficult. If anyone knows how to get diffs to render nicely in Pandoc (perhaps like GitHub renders them) then please contact me.
This is the original implementation, before Mark added wrapper types.
Most of the refactorings that I will perform are independent of what
the implementation actually does; they are simply small changes that
are obviously correct. Some are not obviously correct unless you know
what the program does, so let’s explain that allRolls
does the
following
DiceState
(a list of dice values and an Integer
n
of
rolls left to perform), and alsoDiceChoice
(a choice of which dice to reroll), andInteger
of rolls left to perform.Instead of adding wrapper types let’s just try to improve the design and see what happens.
type DiceChoice = [ Bool ]
type DiceVals = [ Integer ]
type DiceState = (DiceVals, Integer)
allRolls :: DiceChoice > DiceState > [ DiceState ]
= [ ([], n1) ]
allRolls [] ([], n) = undefined
allRolls [] _ :choices) (v:vs, n) =
allRolls (chosen1) >>=
allRolls choices (vs, n> [ (d:roll, n1)  d < rollList ]
\(roll,_) where rollList = if chosen then [v] else [ 1..6 ]
=
example let diceChoices = [ False, True, True, False, False ]
= [ 6, 4, 4, 3, 1 ]
diceVals in mapM_ print $ allRolls diceChoices (diceVals, 2)
There’s a undefined
in there. That is always a red flag. In this
case undefined
occurs when there are dice we could reroll but we
haven’t specifed whether or not to reroll them: the choice list is too
short. Let’s explain that in an error message. It communicates
better to both the end user of the program and the developer.
We don’t need to know what the program does to apply this refactoring but knowing it does give us more confidence that we are doing the right thing.
allRolls :: DiceChoice > DiceState > [ DiceState ]
allRolls [] ([], n) = [ ([], n1) ]
allRolls [] _ = undefined
+allRolls [] _ =
+ error "Invariant violated: choices must be same length as vals"
allRolls (chosen:choices) (v:vs, n) =
allRolls choices (vs, n1) >>=
\(roll,_) > [ (d:roll, n1)  d < rollList ]
I prefer to have as few overlapping patterns as possible, even
“catchall” (_
) patterns. This is a fairly minor change, but let’s
do it anyway. I think it modestly improves the design.
We don’t need to know what the program does to apply this refactoring.
allRolls :: DiceChoice > DiceState > [ DiceState ]
allRolls [] ([], n) = [ ([], n1) ]
allRolls [] _ =
+allRolls [] (_:_, _) =
error "Invariant violated: choices must be same length as vals"
There’s actually a missing pattern (which Wall
will pick up).
Let’s add it. Another modest improvement.
Like with the first invariant check, we don’t need to know what the program does to apply this refactoring but knowing it does give us more confidence that we are doing the right thing.
allRolls :: DiceChoice > DiceState > [ DiceState ]
allRolls [] ([], n) = [ ([], n1) ]
allRolls [] (_:_, _) =
error "Invariant violated: choices must be same length as vals"
+allRolls (_:_) ([], _) =
+ error "Invariant violated: choices must be same length as vals"
pop
functionThere are two distinct things that allRolls
does.
Let’s separate the concerns by adding a pop
function that does 1.
Note that the interface between pop
and allRolls
has type safety!
Once pop
returns, an invalid state is not possible. allRolls
does
not change, except to pass its argument through pop
.
We don’t need to know what the program does to apply this refactoring.
pop :: DiceChoice
> DiceVals
> Maybe ((Bool, Integer), (DiceChoice, DiceVals))
= Nothing
pop [] [] :choices) (v:vs) = Just ((chosen, v), (choices, vs))
pop (chosen:_) [] = error "Invariant violated: missing val"
pop (_:_) = error "Invariant violated: missing choice"
pop [] (_
allRolls :: DiceChoice > DiceState > [ DiceState ]
= case pop choices vs of
allRolls choices (vs, n) Nothing > [ ([], n1) ]
Just ((chosen, v), (choices, vs)) >
1) >>=
allRolls choices (vs, n> [ (d:roll, n1)  d < rollList ]
\(roll,_) where rollList = if chosen then [v] else [ 1..6 ]
This is the first time we have to apply real thinking to the design
process. Weirdly, the n1
argument to the recursive call to
allRolls
is not used in the final result. The only way I can
suggest that one discovers this is to think through how the the code
actually works. Unlike the above changes, this is not just a simple
refactoring.
Let’s indicate that the argument is unused by applying an error
instead. In a language without lazy evaluation you might like to
apply some nonsense value like 999999999
instead, and check that
the results of the function call are not nonsense!
When we run this we don’t get a crash, which implies that that argument was indeed not used.
allRolls choices (vs, n) = case pop choices vs of
Nothing > [ ([], n1) ]
Just ((chosen, v), (choices, vs)) >
 allRolls choices (vs, n1) >>=
+ allRolls choices (vs, error "Didn't expect to use") >>=
\(roll,_) > [ (d:roll, n1)  d < rollList ]
where rollList = if chosen then [v] else [ 1..6 ]
Given the observation above I see no reason to package the DiceVals
and the Integer
together. Let’s prepare to separate them.
We don’t need to know what the program does to apply this refactoring.
We just have to observe that the DiceVals
and the Integer
are not
really used together.
type DiceChoice = [ Bool ]
type DiceVals = [ Integer ]
type DiceState = (DiceVals, Integer)
...
allRolls :: DiceChoice > DiceState > [ DiceState ]
+allRolls :: DiceChoice
+ > (DiceVals, Integer)
+ > [ (DiceVals, Integer) ]
Now let’s do the separation of the arguments. The size of the diff makes the change seem bigger than it is. It is merely passing two arguments instead of a tuple!
We don’t need to know what the program does to apply this refactoring.
allRolls :: DiceChoice
 > (DiceVals, Integer)
+ > DiceVals
+ > Integer
> [ (DiceVals, Integer) ]
allRolls choices (vs, n) = case pop choices vs of
+allRolls choices vs n = case pop choices vs of
Nothing > [ ([], n1) ]
Just ((chosen, v), (choices, vs)) >
 allRolls choices (vs, error "Didn't expect to use") >>=
+ allRolls choices vs (error "Didn't expect to use") >>=
\(roll,_) > [ (d:roll, n1)  d < rollList ]
where rollList = if chosen then [v] else [ 1..6 ]
example =
let diceChoices = [ False, True, True, False, False ]
diceVals = [ 6, 4, 4, 3, 1 ]
 in mapM_ print $ allRolls diceChoices (diceVals, 2)
+ in mapM_ print $ allRolls diceChoices diceVals 2
Once we have separated DiceVals
from the Integer
we notice that
DiceChoice
and DiceVals
seem to naturally belong together. Again
the diff makes the change look bigger than it is. We’re just passing
DiceChoice
and DiceVals
as a tuple rather than two arguments.
We don’t need to know what the program does to apply this refactoring.
pop :: DiceChoice
 > DiceVals
+pop :: (DiceChoice, DiceVals)
> Maybe ((Bool, Integer), (DiceChoice, DiceVals))
pop [] [] = Nothing
pop (chosen:choices) (v:vs) = Just ((chosen, v), (choices, vs))
pop (_:_) [] = error "Invariant violated: missing val"
pop [] (_:_) = error "Invariant violated: missing choice"
+pop ([], []) = Nothing
+pop (chosen:choices, v:vs) = Just ((chosen, v), (choices, vs))
+pop (_:_, []) = error "Invariant violated: missing val"
+pop ([], _:_) = error "Invariant violated: missing choice"
allRolls :: DiceChoice
 > DiceVals
+allRolls :: (DiceChoice, DiceVals)
> Integer
> [ (DiceVals, Integer) ]
allRolls choices vs n = case pop choices vs of
+allRolls (choices, vs) n = case pop (choices, vs) of
Nothing > [ ([], n1) ]
Just ((chosen, v), (choices, vs)) >
 allRolls choices vs (error "Didn't expect to use") >>=
+ allRolls (choices, vs) (error "Didn't expect to use") >>=
\(roll,_) > [ (d:roll, n1)  d < rollList ]
where rollList = if chosen then [v] else [ 1..6 ]
example =
let diceChoices = [ False, True, True, False, False ]
diceVals = [ 6, 4, 4, 3, 1 ]
 in mapM_ print $ allRolls diceChoices diceVals 2
+ in mapM_ print $ allRolls (diceChoices, diceVals) 2
We no longer need to unpack the tuple!
We don’t need to know what the program does to apply this refactoring.
allRolls (choices, vs) n = case pop (choices, vs) of
+allRolls t n = case pop t of
Nothing > [ ([], n1) ]
 Just ((chosen, v), (choices, vs)) >
 allRolls (choices, vs) (error "Didn't expect to use") >>=
+ Just ((chosen, v), t) >
+ allRolls t (error "Didn't expect to use") >>=
Integer
. Make this structural.Given that we have an unused argument in the recursive call let’s see
if we can change our design to make this obvious, i.e. make the fact
that we don’t use it an essential part of the structure of the
program, not just a property. In this case it amounts to pairing the
rolls with n1
after the bulk of the algorithm (allRollsNoN
) has
finished.
This is the second time we have to actually analyse how our program works rather than just apply a mechanical translation.
allRolls :: (DiceChoice, DiceVals)
> Integer
> [ (DiceVals, Integer) ]
allRolls t n = case pop t of
 Nothing > [ ([], n1) ]
+allRolls t n = [ (vals, n1)  vals < allRollsNoN t ]
+
+allRollsNoN :: (DiceChoice, DiceVals) > [ DiceVals ]
+allRollsNoN t = case pop t of
+ Nothing > [ [] ]
Just ((chosen, v), t) >
 allRolls t (error "Didn't expect to use") >>=
 \(roll,_) > [ (d:roll, n1)  d < rollList ]
+ allRollsNoN t >>=
+ \roll > [ d:roll  d < rollList ]
where rollList = if chosen then [v] else [ 1..6 ]
Given that DiceChoice
and DiceVals
seem to belong together
let’s add a type synonym (DiceTurn
) for that.
We don’t need to know what the program does to apply this refactoring. We just observe that the pair of things are always used together.
+type DiceTurn = (DiceChoice, DiceVals)
pop :: (DiceChoice, DiceVals)
 > Maybe ((Bool, Integer), (DiceChoice, DiceVals))
+pop :: DiceTurn
+ > Maybe ((Bool, Integer), DiceTurn)
pop ([], []) = Nothing
pop (chosen:choices, v:vs) = Just ((chosen, v), (choices, vs))
pop (_:_, []) = error "Invariant violated: missing val"
pop ([], _:_) = error "Invariant violated: missing choice"
allRolls :: (DiceChoice, DiceVals)
+allRolls :: DiceTurn
> Integer
> [ (DiceVals, Integer) ]
allRolls t n = [ (vals, n1)  vals < allRollsNoN t ]
allRollsNoN :: (DiceChoice, DiceVals) > [ DiceVals ]
+allRollsNoN :: DiceTurn > [ DiceVals ]
Our invariant is that the number of DiceChoice
s must be the same as the
number of DiceVals
. Semantically, we actually want something
stronger: each of the DiceChoice
s corresponds to exactly one of the
DiceVals
. In my experience this is the single most common
nontrival failure to structurally enforce program behaviour (and I’m
not the only one to see
it).
The fix is to put pairs of dice choice and dice vals in the same list! We can entirely remove our invariant check. The invariant is enforced by the type.
Consumers will have to change too but they’ll be better off for it!
In example
I just zip
ped the args. It could also be something
much better.
type DiceChoice = [ Bool ]
type DiceVals = [ Integer ]
type DiceTurn = (DiceChoice, DiceVals)
+type DiceTurn = [(Bool, Integer)]
pop :: DiceTurn
> Maybe ((Bool, Integer), DiceTurn)
pop ([], []) = Nothing
pop (chosen:choices, v:vs) = Just ((chosen, v), (choices, vs))
pop (_:_, []) = error "Invariant violated: missing val"
pop ([], _:_) = error "Invariant violated: missing choice"
+pop [] = Nothing
+pop (a:as) = Just (a, as)
allRolls :: DiceTurn
> Integer
@@ 25,4 +22,4 @@ allRollsNoN t = case pop t of
example =
let diceChoices = [ False, True, True, False, False ]
diceVals = [ 6, 4, 4, 3, 1 ]
 in mapM_ print $ allRolls (diceChoices, diceVals) 2
+ in mapM_ print $ allRolls (zip diceChoices diceVals) 2
uncons
Having done that we see that pop
is just the standard function
“uncons
”.
We don’t need to know what the program does to apply this refactoring.
+import Data.List (uncons)
+
type DiceVals = [ Integer ]
type DiceTurn = [(Bool, Integer)]
pop :: DiceTurn
 > Maybe ((Bool, Integer), DiceTurn)
pop [] = Nothing
pop (a:as) = Just (a, as)

allRolls :: DiceTurn
> Integer
> [ (DiceVals, Integer) ]
allRolls t n = [ (vals, n1)  vals < allRollsNoN t ]
allRollsNoN :: DiceTurn > [ DiceVals ]
allRollsNoN t = case pop t of
+allRollsNoN t = case uncons t of
Having said that, we don’t actually need uncons
. We can just
pattern match directly.
We don’t need to know what the program does to apply this refactoring.
allRollsNoN :: DiceTurn > [ DiceVals ]
allRollsNoN t = case uncons t of
 Nothing > [ [] ]
 Just ((chosen, v), t) >
+allRollsNoN t = case t of
+ [] > [ [] ]
+ (chosen, v):t >
The use of the bind operator (>>=
) and list comprehension are not
particularly clear. Let’s rewrite it to use do notation. (In fact I
recommend defaulting to do notation over operators unless there’s some
compelling readability benefit to using the latter.)
We don’t need to know what the program does to apply this refactoring.
allRollsNoN :: DiceTurn > [ DiceVals ]
allRollsNoN t = case t of
[] > [ [] ]
 (chosen, v):t >
 allRollsNoN t >>=
 \roll > [ d:roll  d < rollList ]
+ (chosen, v):t > do
+ roll < allRollsNoN t
+ d < rollList
+ [ d:roll ]
mapM
We can see from the above that what our program does is takes the head
of a list, runs recursively on the tail, does something to the head,
and then puts it back on the tail. This is a “map” operation.
Specifically in this case we are mapping in a monad so we use mapM
.
In modern Haskell you’d use traverse
, but I’m going to stick to
mapM
because traverse
does not read so well. (In my opinion traverse
really
ought to be called mapA
but others don’t like the idea of that
change.)
In this change we just make the function we are mapping take explicit
arguments. We’ll switch to use mapM
in the next change.
We don’t need to know what the program does to apply this refactoring.
(chosen, v):t > do
roll < allRollsNoN t
 d < rollList
+ d < rollList (chosen, v)
[ d:roll ]
 where rollList = if chosen then [v] else [ 1..6 ]
+ where rollList (chosen, v)
+ = if chosen then [v] else [ 1..6 ]
mapM
Now we can just use mapM
directly.
We don’t need to know what the program does to apply this refactoring
but we do need to know the general concept of “mapping” and the
specific implementation mapM
. Be careful! This particular
“refactoring” actually reverses the order of effects – the list of
dice rolls will come out in a different order.
allRollsNoN t = case t of
 [] > [ [] ]
 (chosen, v):t > do
 roll < allRollsNoN t
 d < rollList (chosen, v)
 [ d:roll ]
 where rollList (chosen, v)
 = if chosen then [v] else [ 1..6 ]
+allRollsNoN =
+ mapM (\(chosen, v) > if chosen then [v] else [ 1..6 ])
There’s ambiguity in the type DiceTurn = [(Bool, Integer)]
. Does
the Bool
refer to whether we keep the dice or to whether we reroll
them? There’s no way for me to tell without seeing this conditional
inside the function:
if chosen then [v] else [ 1..6 ]
Ah, so the Bool
refers to whether we keep the dice. Perhaps this
is written in the documentation somewhere, but why do I believe that
the documentation is kept in line with the implementation? I want a
single source of truth!
Let’s add a type to avoid “boolean blindness”. The type of
allRollsBetter
still does not guarantee that the implementation does
the right thing with its argument but it does make any deviation
glaringly obvious.
We don’t need to know what the program does to apply this refactoring.
It requires the uncontroversial LambdaCase
language extension.
allRollsNoN =
 mapM (\(chosen, v) > if chosen then [v] else [ 1..6 ])
+allRollsNoN = allRollsBetter . map fromTurn
+
+data DiceChoice = Keep Integer  Reroll
+
+fromTurn :: (Bool, Integer) > DiceChoice
+fromTurn (chosen, v) = if chosen then Keep v else Reroll
+
+allRollsBetter :: [DiceChoice] > [ DiceVals ]
+allRollsBetter = mapM $ \case
+ Reroll > [ 1..6 ]
+ Keep v > [v]
Let’s get rid of all vestiges of the old version. What allRolls
does could be done more clearly at the call site. At this point I
wouldn’t add wrapper types for “type safety”. The rest of the program
might be sufficiently complex that they would help, but they certainly
don’t add anything in this simple example.
The new version communicates much better. We “map” over our
DiceVals
list, that is, apply a function to each element in turn.
In this case we’re taking advantage of the Monad
instance for lists,
so we use mapM
. The function we map simply says
Reroll
? If so, the possible results are [1..6]
Keep v
? If so, the possible results are just
[v]
”{# LANGUAGE LambdaCase #}
type DiceVals = [Integer]
data DiceChoice = Keep Integer  Reroll
allRollsBetter :: [DiceChoice] > [DiceVals]
= mapM $ \case
allRollsBetter Reroll > [1..6]
Keep v > [v]
=
example let diceVals = [ Reroll, Keep 4, Keep 4, Reroll, Reroll ]
in mapM_ print $ allRollsBetter diceVals
Look at allRollsBetter
in comparison to the original allRolls
!
allRolls :: DiceChoice > DiceState > [ DiceState ]
= [ ([], n1) ]
allRolls [] ([], n) = undefined
allRolls [] _ :choices) (v:vs, n) =
allRolls (chosen1) >>=
allRolls choices (vs, n> [ (d:roll, n1)  d < rollList ]
\(roll,_) where rollList = if chosen then [v] else [ 1..6 ]
How did we end up with something so much clearer? We applied a sequence of transformations to improve the design, almost all of which are applicable in any language. The transformations were partly informed by a notion of “type safety”. Specifically, we aimed to model our domain using types and functions that make illegal states unrepresentable.
None of this requires a language like Haskell. It would be good
design in Python as well. One of Python’s weaknesses is that it makes
dealing with sum types awkward. We would have had to take a slightly
different approach for the Maybe
returned by pop
(probably None
or a tuple), the DiceChoice
type (probably a pair of classes) and
the list monad (probably just a recursive generator function).
Ultimately though, the benefit of Haskell is not that it allows us to
implement welltyped designs, nor particularly that it forbids us from
implementing illtyped designs. The benefit is that it nudges us away
from poorlytyped, poorlystructured designs and holds our hand as it
does so.